[KULIAH]Statistic & Probability

[letyou[die]]

Buat agan2 yang ngak mood buat nyatat waktu di kelas atau ngantuk atau apalah 
saya akan coba bantu dengan theard ini . 

semua yang di kelas saya buat jadi singkat , hingga agan2 bisa simak dan lajar yah
 

semangat 

[letyou[die]]

  ini dia sebelum melangkah lanjut agan-agan musti tau dasar statistic
nich........


FREQUENCY DISTRIBUTION
Exclusife class interval a <= x < b
Inclusife class interval a <= x <= b

Suggested C.I = (Max value-Min value)/(1+3.322 (log⁡〖total observation〗 )

CENTRAL TENDENCY
The measure of central tendency is a number used to represent the centre or middle of a set of data values. There are three types to determine central tendency
   


P.S:
   Fi= frequency of 1th class interval
   Xi= mid value of 1th class interval
   ∑fi= total frequency
   
   n= total frequency
   L= lower limit of median class
   m= C.M of the previous class
   f= frequency of median class
   h= class interval

   fm=max frequency
   f1= preceding frequency to the modal class
   f2= succeeding frequency to the modal class

[DarkAssilum]

da baca tu bahasa riki saki eh     

kurang so dengar bahasa inggris di klas kong musti baca bahasa inggris di forum leh   

btw, supaya nya OOT / JUNK

Tugas yang terakhir da dapa untuk kelas statistic & probability jam 10.00

List of Weights (in pounds) : 204, 207, 208, 212, 214, 215

a. Variance = 15.667 pounds
b. Standard Deviation = 3.95 pounds

selengkapnya....

Code: [Select]

http://wodrow.blogspot.com/2011/10/standard-deviation-on-ungrouped-data.html

[bulllzzz]

da baca tu bahasa riki saki eh     

kurang so dengar bahasa inggris di klas kong musti baca bahasa inggris di forum leh   

btw, supaya nya OOT / JUNK

Tugas yang terakhir da dapa untuk kelas statistic & probability jam 10.00

List of Weights (in pounds) : 204, 207, 208, 212, 214, 215

a. Variance = 15.667 pounds
b. Standard Deviation = 3.95 pounds

selengkapnya....

Code: [Select]

http://wodrow.blogspot.com/2011/10/standard-deviation-on-ungrouped-data.html

ah.. itu so dp jawaban??

 

[DarkAssilum]

jangan junk disini buls   

[letyou[die]]

oke agan-agan ini kelanjutannya dari statistic

Spoiler for Catatan:

 

Spoiler for Catatan 2:

 
gmana ? bisa kan ikut?

masih bingung?

[_Break[Free]_]

slah smua nngi p jwban...
qt sja nda maso kls..
mo taw apa it nngi ada post it..
lbeh bae maen dota...co tax p sandy kwa..

[DarkAssilum]

ah nya perfect qt pe mid 

[letyou[die]]

agan-agan , santai saja walaupun isian kita salah. kan dunia belum berakhir. masih ada semester depan yang mungkin bisa lebih baik lagi

bagimana?
 

tetap semangat agan-agan
 :jempol_zm :jempol_zm

[MyStyLeIsPrO]

1. a pair of dice are thrown
a. what is the probability that the sum of the cut to comes on the two dice is below to 10?
b. what is the probability of geeting some number?

2. A & B are among 20 persons who sit and random along around table any six persons between A&B ?

3. cut of 100.000 new born bubies. 77.181 survived till the age 20 find the probability that a new born survived till 20?

4. A page is opened at random from a book containing 200 pages. what is the probability that the number on the page is perfect square?

5. find the probability that keep year contains 52 mondays?

6. two dice are volled
a. what is the probability that none of the dice shows the number 2 ?
b. probability of the total of at least 8 on two dice?


kumpul sebelum jam 5 besok sore...
4-11-2011...


oi yang management science le kata mo dapa tugas sbntr...

gantian ka kls kong tulis soal...

[Mpo]

ad yg tau soal management science..??

[bulllzzz]

ad yg tau soal management science..??

nda ada tugas mene...

[letyou[die]]

1. A bag contain 5 red balls and some blue ball. prob drawing ball from bag is thrice (three times) that of red balls number blue ball is

solve:
p(R)= 5/x
p(B) = 3. 5/x = 15/x

p(R)+p(B) = 1
5/x + 15/x = 1
20/x=1
20=x

BLue = 20-5= 15

2. A is an random event
p(A) : p(Ac) = 7:12   ->p(A)= 7/19
find p(A)

Solve
p(A) : p(Ac)= 7:12
p(A) + p(Ac)=5
7+12=19
p(A)=7/19

3. ABC, mutually exclusive and exhaustive
p(B) = 3/2 p(A)
p(C)=1/2 p(B) -> 1/2 * 3/2 p(A)
                                   = 3/4p(A)
p(A)=?
exhaustive => p(A υ B υ C)=1

1=p(A) + p(B)+ p(C)
1= p(A) + 3/2 p(A) + 3/4 p(A)
1= p(A) (4/4+3/4+3/4)
1= p(A) (13/4)
p(A)= 1/  13/4
=4/15

[DarkAssilum]

1=p(A) + p(B)+ p(C)
1= p(A) + 3/2 p(A) + 3/4 p(A)
1= p(A) (4/4+3/4+3/4)
1= p(A) (13/4)
p(A)= 1/  13/4
=4/15

yang warna merah tolong di ganti menjadi

p(A)= 1/  13/4
=4/15

[Amakuchi]

Dengan berakhirnya Final Test semester ini, semua thread mata kuliah akan saya lock untuk menghindari junk yang berlebihan di subforum Study Garden. Thread ini akan dibuka kembali pada semester dimana mata kuliah ini tersedia untuk dikontrak.
terima kasih untuk partisipasi pada thread ini sepanjang semester berjalan.
sampai jumpa & have a nice holiday all